JEE Main 2019 (Online) 10th April Evening Slot | Heat and Thermodynamics Question 213 | Physics

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

One mole of ideal gas passes through a process where pressure and volume obey the relation $$P = {P_0}\left[ {1 - {1 \over 2}{{\left( {{{{V_0}} \over V}} \right)}^2}} \right]$$. Here P₀ and V₀ are constants. Calculate the change in the temperature of the gas if its volume changes form V₀ to 2V₀

$${3 \over 4}{{{P_0}{V_0}} \over R}$$

$${1 \over 2}{{{P_0}{V_0}} \over R}$$

$${5 \over 4}{{{P_0}{V_0}} \over R}$$

$${1 \over 4}{{{P_0}{V_0}} \over R}$$

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

Light is incident normally on a completely absorbing surface with an energy flux of 25 W cm^–2. If the surface has an area of 25 cm², the momentum transferred to the surface in 40 min time duration will be :

6.3 × 10^–4 Ns

5.0 × 10^–3 Ns

1.4 × 10^–6 Ns

3.5 × 10^–6 Ns

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

When heat Q is supplied to a diatomic gas of rigid molecules, at constant volume its temperature increases by $$\Delta $$T. the heat required to produce the same change in temperature, at a constant pressure is :

$${7 \over 5}Q$$

$${3 \over 2}Q$$

$${2 \over 3}Q$$

$${5 \over 3}Q$$

JEE Main 2019 (Online) 10th April Morning Slot

MCQ (Single Correct Answer)

-1

A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat needed to raise the temperature of the gas by 20°C is : [Given that R = 8.31 J mol^–1 K^–1]

374 J

700 J

748 J

350 J

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