JEE Main 2020 (Online) 4th September Evening Slot | Heat and Thermodynamics Question 174 | Physics

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

Match the thermodynamic processes taking place in a system with the correct conditions. In the table : $$\Delta $$Q is the heat supplied, $$\Delta $$W is the work done and $$\Delta $$U is change in internal energy of the system.

Process	Condition
(I) Adiabatic	(1) $$\Delta $$W = 0
(II) Isothermal	(2) $$\Delta $$Q = 0
(III) Isochoric	(3) $$\Delta $$U $$ \ne $$ 0, $$\Delta $$W $$ \ne $$ 0, $$\Delta $$Q $$ \ne $$ 0
(IV) Isobaric	(4) $$\Delta $$U = 0

(I) - (1), (II) - (1), (III) - (2), (IV) - (3)

(I) - (2), (II) - (4), (III) - (1), (IV) - (3)

(I) - (1), (II) - (2), (III) - (4), (IV) - (4)

(I) - (2), (II) - (1), (III) - (4), (IV) - (3)

JEE Main 2020 (Online) 4th September Morning Slot

MCQ (Single Correct Answer)

-1

The specific heat of water
= 4200 J kg^-1K^-1 and the latent heat of
ice = 3.4 $$ \times $$ 10⁵ J kg^–1. 100 grams of ice at
0^oC is placed in 200 g of water at 25^oC. The
amount of ice that will melt as the temperature
of water reaches 0^oC is close to (in grams) :

63.8

61.7

69.3

64.6

JEE Main 2020 (Online) 4th September Morning Slot

MCQ (Single Correct Answer)

-1

Match the $${{{C_P}} \over {{C_V}}}$$ ratio for ideal gases with different type of molecules :

Molecule Type	C_P/C_V
(A) Monatomic	(I) 7/5
(B) Diatomic rigid molecules	(II) 9/7
(C) Diatomic non-rigid molecules	(III) 4/3
(D) Triatomic rigid molecules	(IV) 5/3

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

JEE Main 2020 (Online) 3rd September Evening Slot

MCQ (Single Correct Answer)

-1

A metallic sphere cools from 50^oC to 40^o in 300 s. If atmospheric temperature around is 20^oC, then the sphere’s temperature after the next 5 minutes will be close to :

35^oC

31^oC

33^oC

28^oC

PREVIOUS NEXT