JEE Main 2018 (Online) 16th April Morning Slot | Heat and Thermodynamics Question 368 | Physics

One mole of an ideal monoatomic gas is taken along the path ABCA as show in the PV diagram. The maximum temperature attained by the gas along the path BC is given by :

JEE Main 2018 (Online) 16th April Morning Slot Physics - Heat and Thermodynamics Question 380 English

JEE Main 2018 (Online) 16th April Morning Slot Physics - Heat and Thermodynamics Question 380 English

$${{25} \over {16}}\,{{{P_o}{V_o}} \over R}$$

$${{25} \over {8}}\,{{{P_o}{V_o}} \over R}$$

$${{25} \over {4}}\,{{{P_o}{V_o}} \over R}$$

$${{5} \over {8}}\,{{{P_o}{V_o}} \over R}$$

JEE Main 2018 (Online) 16th April Morning Slot

MCQ (Single Correct Answer)

-1

Two moles of helium are mixed with n moles of hydrogen. If $${{Cp} \over {Cv}} = {3 \over 2}$$ for the mixture, then the value of n is :

3 / 2

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

-1

Two moles of an ideal monatomic gas occupies a volume V at 27^oC. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.

(a) 195 K (b) 2.7 kJ

(a) 189 K (b) 2.7 kJ

(a) 195 K (b) –2.7 kJ

(a) 189 K (b) – 2.7 kJ

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

-1

The value closest to the thermal velocity of a Helium atom at room temperature (300 K) in ms^-1 is :
[k_B =1.4 $$ \times $$ 10^-23 J/K; m_He = 7 $$ \times $$ 10 ^-27 kg ]

1.3 $$ \times $$ 10⁴

1.3 $$ \times $$ 10³

1.3 $$ \times $$ 10⁵

1.3 $$ \times $$ 10²

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