JEE Main 2021 (Online) 17th March Evening Shift | Heat and Thermodynamics Question 199 | Physics

If one mole of the polyatomic gas is having two vibrational modes and $$\beta$$ is the ratio of molar specific heats for polyatomic gas $$\left( {\beta = {{{C_P}} \over {{C_V}}}} \right)$$ then the value of $$\beta$$ is :

1.02

1.35

1.2

1.25

JEE Main 2021 (Online) 17th March Evening Shift

MCQ (Single Correct Answer)

-1

Which one is the correct option for the two different thermodynamic processes?

JEE Main 2021 (Online) 17th March Evening Shift Physics - Heat and Thermodynamics Question 199 English 1

JEE Main 2021 (Online) 17th March Evening Shift Physics - Heat and Thermodynamics Question 199 English 1

JEE Main 2021 (Online) 17th March Evening Shift Physics - Heat and Thermodynamics Question 199 English 2

JEE Main 2021 (Online) 17th March Evening Shift Physics - Heat and Thermodynamics Question 199 English 3

JEE Main 2021 (Online) 17th March Evening Shift Physics - Heat and Thermodynamics Question 199 English 4

(a) only

(b) and (c)

JEE Main 2021 (Online) 17th March Morning Shift

MCQ (Single Correct Answer)

-1

A polyatomic ideal gas has 24 vibrational modes. What is the value of $$\gamma$$?

1.37

1.30

1.03

10.3

JEE Main 2021 (Online) 17th March Morning Shift

MCQ (Single Correct Answer)

-1

Two ideal polyatomic gases at temperatures T₁ and T₂ are mixed so that there is no loss of energy. If F₁ and F₂, m₁ and m₂, n₁ and n₂ be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{F_1} + {F_2}}}$$

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{n_1}{F_1} + {n_2}{F_2}}}$$

$${{{n_1}{T_1} + {n_2}{T_2}} \over {{n_1} + {n_2}}}$$

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{n_1} + {n_2}}}$$

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