JEE Main 2019 (Online) 12th April Morning Slot | Heat and Thermodynamics Question 210 | Physics

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is –180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc. The work done by the gas along the path abc is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Heat and Thermodynamics Question 212 English

JEE Main 2019 (Online) 12th April Morning Slot Physics - Heat and Thermodynamics Question 212 English

120 J

130 J

100 J

140 J

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

Two moles of helium gas is mixed with three moles of hydrogen molecules (taken to be rigid). What is the molar specific heat of mixture at constant volume ? (R = 8.3 J/mol K)

21.6 J/mol K

17.4 J/mol K

15.7 J/mol K

19.7 J/mol K

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

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When M₁ gram of ice at –10^oC (specific heat = 0.5 cal g^–1 ^oC^–1 ) is added to M₂ gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g^–1 is :

$${{50{M_2}} \over {{M_1}}} - 5$$

$${{50{M_2}} \over {{M_1}}}$$

$${{5{M_2}} \over {{M_1}}} - 5$$

$${{5{M_1}} \over {{M_2}}} - 50$$

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

One mole of ideal gas passes through a process where pressure and volume obey the relation $$P = {P_0}\left[ {1 - {1 \over 2}{{\left( {{{{V_0}} \over V}} \right)}^2}} \right]$$. Here P₀ and V₀ are constants. Calculate the change in the temperature of the gas if its volume changes form V₀ to 2V₀

$${3 \over 4}{{{P_0}{V_0}} \over R}$$

$${1 \over 2}{{{P_0}{V_0}} \over R}$$

$${5 \over 4}{{{P_0}{V_0}} \over R}$$

$${1 \over 4}{{{P_0}{V_0}} \over R}$$

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