1
JEE Main 2024 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

A diatomic gas $$(\gamma=1.4)$$ does $$100 \mathrm{~J}$$ of work in an isobaric expansion. The heat given to the gas is :

A
150 J
B
490 J
C
350 J
D
250 J
2
JEE Main 2024 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Given below are two statements :

Statement (I) : The mean free path of gas molecules is inversely proportional to square of molecular diameter.

Statement (II) : Average kinetic energy of gas molecules is directly proportional to absolute temperature of gas.

In the light of the above statements, choose the correct answer from the options given below :

A
Statement I is false but Statement II is true
B
Both Statement I and Statement II are true
C
Statement I is true but Statement II is false
D
Both Statement I and Statement II are false
3
JEE Main 2024 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature $$(27^{\circ} \mathrm{C})$$. The ratio of specific heat of gases at constant volume respectively is:

A
$$\frac{3}{2}$$
B
$$\frac{3}{5}$$
C
$$\frac{7}{5}$$
D
$$\frac{5}{3}$$
4
JEE Main 2024 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two different adiabatic paths for the same gas intersect two isothermal curves as shown in P-V diagram. The relation between the ratio $$\frac{V_a}{V_d}$$ and the ratio $$\frac{V_b}{V_c}$$ is:

JEE Main 2024 (Online) 8th April Morning Shift Physics - Heat and Thermodynamics Question 10 English

A
$$\frac{V_a}{V_d} \neq \frac{V_b}{V_c}$$
B
$$\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^{-1}$$
C
$$\frac{V_a}{V_d}=\frac{V_b}{V_c}$$
D
$$\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^2$$
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