JEE Main 2023 (Online) 6th April Evening Shift | Electromagnetic Waves Question 31 | Physics

The energy density associated with electric field $$\vec{E}$$ and magnetic field $$\vec{B}$$ of an electromagnetic wave in free space is given by $$\left(\epsilon_{0}-\right.$$ permittivity of free space, $$\mu_{0}-$$ permeability of free space)

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

JEE Main 2023 (Online) 6th April Morning Shift

MCQ (Single Correct Answer)

-1

For the plane electromagnetic wave given by $$E=E_{0} \sin (\omega t-k x)$$ and $$B=B_{0} \sin (\omega t-k x)$$, the ratio of average electric energy density to average magnetic energy density is

1/2

JEE Main 2023 (Online) 1st February Evening Shift

MCQ (Single Correct Answer)

-1

The ratio of average electric energy density and total average energy density of electromagnetic wave is :

$$\frac{1}{2}$$

JEE Main 2023 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

Match List I with List II :

	List I		List II
A.	Microwaves	I.	Radio active decay of the nucleus
B.	Gamma rays	II.	Rapid acceleration and deceleration of electron in aerials
C.	Radio waves	III.	Inner shell electrons
D.	X-rays	IV.	Klystron valve