JEE Main 2019 (Online) 9th January Evening Slot | Magnetics Question 204 | Physics

JEE Main 2019 (Online) 9th January Evening Slot

MCQ (Single Correct Answer)

-1

The energy associated with electric field is (U_E) and with magnetic field is (U_B) for an electromagnetic wave in free space. Then :

$${U_E} = {{{U_B}} \over 2}$$

$${U_E} > {U_B}$$

$${U_E} < {U_B}$$

$${U_E} = {U_B}$$

JEE Main 2019 (Online) 9th January Evening Slot

MCQ (Single Correct Answer)

-1

A particle having the same charge as of electron moves in a ciurcular path of radius 0.5 cm under the influence of a magnetic field 0f 0.5 T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron = 1.6 $$ \times $$ 10$$-$$¹⁹C)

9.1 $$ \times $$ 10^$$-$$31 kg

1.6 $$ \times $$ 10^$$-$$27 kg

1.6 $$ \times $$ 10^$$-$$19 kg

2.0 $$ \times $$ 10^$$-$$24 kg

JEE Main 2019 (Online) 9th January Evening Slot

MCQ (Single Correct Answer)

-1

One of the two identical conducting wires of length L is bent in the form of a circular loop and the other one into a circular coil of N identical turns. If the same current is passed in both, the radio of the magnetic field at the central of the loop (B_L) to that at the center of the coil (B_C), i.e. $${{{B_L}} \over {{B_C}}}$$ will be :

$${1 \over N}$$

N²

$${1 \over {{N^2}}}$$

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

A current loop, having two circular arcs joined by two radial lines is shown in the figure. It carries a current of 10 A. The magnetic field at point O will be close to :

JEE Main 2019 (Online) 9th January Morning Slot Physics - Magnetics Question 211 English