JEE Main 2023 (Online) 10th April Evening Shift | Electromagnetic Waves Question 29 | Physics

The amplitude of magnetic field in an electromagnetic wave propagating along y-axis is $$6.0 \times 10^{-7} \mathrm{~T}$$. The maximum value of electric field in the electromagnetic wave is

$$6.0 \times 10^{-7} ~\mathrm{Vm}^{-1}$$

$$5 \times 10^{14} ~\mathrm{Vm}^{-1}$$

$$180 ~\mathrm{Vm}^{-1}$$

$$2 \times 10^{15} ~\mathrm{Vm}^{-1}$$

JEE Main 2023 (Online) 10th April Morning Shift

MCQ (Single Correct Answer)

-1

The energy of an electromagnetic wave contained in a small volume oscillates with

double the frequency of the wave

the frequency of the wave

half the frequency of the wave

zero frequency

JEE Main 2023 (Online) 6th April Evening Shift

MCQ (Single Correct Answer)

-1

The energy density associated with electric field $$\vec{E}$$ and magnetic field $$\vec{B}$$ of an electromagnetic wave in free space is given by $$\left(\epsilon_{0}-\right.$$ permittivity of free space, $$\mu_{0}-$$ permeability of free space)

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

JEE Main 2023 (Online) 6th April Morning Shift

MCQ (Single Correct Answer)

-1

For the plane electromagnetic wave given by $$E=E_{0} \sin (\omega t-k x)$$ and $$B=B_{0} \sin (\omega t-k x)$$, the ratio of average electric energy density to average magnetic energy density is