1
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A monochromatic beam of light has a frequency $$v = {3 \over {2\pi }} \times {10^{12}}Hz$$ and is propagating along the direction $${{\widehat i + \widehat j} \over {\sqrt 2 }}.$$
It is polarized along the $$\widehat k$$ direction. The acceptable form for the magnetic field is :
A
JEE Main 2018 (Online) 15th April Morning Slot Physics - Alternating Current and Electromagnetic Induction Question 188 English Option 1
B
JEE Main 2018 (Online) 15th April Morning Slot Physics - Alternating Current and Electromagnetic Induction Question 188 English Option 2
C
JEE Main 2018 (Online) 15th April Morning Slot Physics - Alternating Current and Electromagnetic Induction Question 188 English Option 3
D
JEE Main 2018 (Online) 15th April Morning Slot Physics - Alternating Current and Electromagnetic Induction Question 188 English Option 4
2
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An ideal capacitor of capacitance $$0.2\,\mu F$$ is charged to a potential difference of $$10$$ $$V.$$ The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance $$0.5$$ $$mH.$$ The current at a time when the potential difference across the capacitor is $$5$$ $$V,$$ is :
A
$$0.34\,\,A$$
B
$$0.25\,\,A$$
C
$$0.17\,\,A$$
D
$$0.15\,\,A$$
3
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
A sinusoidal voltage of peak value 283 V and angular frequency 320/s is applied to a series LCR circuit. Given that R=5 $$\Omega $$, L=25 mH and C=1000 $$\mu $$F. The total impedance, and phase difference between the voltage across the source and the current will respectively be :
A
10 $$\Omega $$ and tan$$-$$1 $$\left( {{5 \over 3}} \right)$$
B
$$7\,\Omega $$ and 45o
C
$$10\,\Omega $$ and tan$$-$$1$$\left( {{8 \over 3}} \right)$$
D
$$7\,\Omega $$ and tan$$-$$1$$\left( {{5 \over 3}} \right)$$
4
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
The electric field component of a monochromatic radiation is given by

$$\overrightarrow E $$ = 2 E0 $$\widehat i$$ cos kz cos $$\omega $$t

Its magnetic field $$\overrightarrow B $$ is then given by :
A
$${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz cos $$\omega $$t
B
$$-$$ $${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz sin $$\omega $$t
C
$${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz sin $$\omega $$t
D
$${{2{E_0}} \over c}$$ $$\widehat j$$ cos kz cos $$\omega $$t
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