1
JEE Main 2023 (Online) 24th January Evening Shift
+4
-1

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$

$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$

Then the correct relation between E$$_0$$ and B$$_0$$ is given by

A
$$\mathrm{{E_o}{B_o} = \omega k}$$
B
$$\mathrm{{E_0} = k{B_0}}$$
C
$$\mathrm{k{E_0} = \omega {B_0}}$$
D
$$\mathrm{\omega {E_0} = k{B_0}}$$
2
JEE Main 2023 (Online) 24th January Morning Shift
+4
-1

In $$\overrightarrow E$$ and $$\overrightarrow K$$ represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector is given by :

($$\omega$$ - angular frequency) :

A
$${1 \over \omega }\left( {\overline K \times \overline E } \right)$$
B
$$\overline K \times \overline E$$
C
$$\omega \left( {\overline K \times \overline E } \right)$$
D
$$\omega \left( {\overline E \times \overline K } \right)$$
3
JEE Main 2022 (Online) 29th July Morning Shift
+4
-1

Match List - I with List - II :

List - I List - II
(a) UV rays (i) Diagnostic tool in medicine
(b) X-rays (ii) Water purification
(d) Infrared wave (iv) Improving visibility in foggy days

Choose the correct answer from the options given below :

A
(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
B
(a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
C
(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
D
(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
4
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

Sun light falls normally on a surface of area $$36 \mathrm{~cm}^{2}$$ and exerts an average force of $$7.2 \times 10^{-9} \mathrm{~N}$$ within a time period of 20 minutes. Considering a case of complete absorption, the energy flux of incident light is

A
$$25.92 \times 10^{2} \mathrm{~W} / \mathrm{cm}^{2}$$
B
$$8.64 \times 10^{-6} \mathrm{~W} / \mathrm{cm}^{2}$$
C
$$6.0 \mathrm{~W} / \mathrm{cm}^{2}$$
D
$$0.06\mathrm{~W} / \mathrm{cm}^{2}$$
EXAM MAP
Medical
NEET