1
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$

$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$

Then the correct relation between E$$_0$$ and B$$_0$$ is given by

A
$$\mathrm{{E_o}{B_o} = \omega k}$$
B
$$\mathrm{{E_0} = k{B_0}}$$
C
$$\mathrm{k{E_0} = \omega {B_0}}$$
D
$$\mathrm{\omega {E_0} = k{B_0}}$$
2
JEE Main 2023 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In $$\overrightarrow E $$ and $$\overrightarrow K $$ represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector is given by :

($$\omega$$ - angular frequency) :

A
$${1 \over \omega }\left( {\overline K \times \overline E } \right)$$
B
$$\overline K \times \overline E $$
C
$$\omega \left( {\overline K \times \overline E } \right)$$
D
$$\omega \left( {\overline E \times \overline K } \right)$$
3
JEE Main 2022 (Online) 29th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List - I with List - II :

List - I List - II
(a) UV rays (i) Diagnostic tool in medicine
(b) X-rays (ii) Water purification
(c) Microwave (iii) Communication, Radar
(d) Infrared wave (iv) Improving visibility in foggy days

Choose the correct answer from the options given below :

A
(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
B
(a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
C
(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
D
(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
4
JEE Main 2022 (Online) 28th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Sun light falls normally on a surface of area $$36 \mathrm{~cm}^{2}$$ and exerts an average force of $$7.2 \times 10^{-9} \mathrm{~N}$$ within a time period of 20 minutes. Considering a case of complete absorption, the energy flux of incident light is

A
$$25.92 \times 10^{2} \mathrm{~W} / \mathrm{cm}^{2}$$
B
$$8.64 \times 10^{-6} \mathrm{~W} / \mathrm{cm}^{2}$$
C
$$6.0 \mathrm{~W} / \mathrm{cm}^{2}$$
D
$$0.06\mathrm{~W} / \mathrm{cm}^{2}$$
JEE Main Subjects
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12