1
JEE Main 2023 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which of the following are true?

A. Speed of light in vacuum is dependent on the direction of propagation.

B. Speed of light in a medium is independent of the wavelength of light.

C. The speed of light is independent of the motion of the source.

D. The speed of light in a medium is independent of intensity.

Choose the correct answer from the options given below:

A
B and D only
B
B and C only
C
A and C only
D
C and D only
2
JEE Main 2023 (Online) 25th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

List I List II
A. Gauss's Law in Electrostatics I. $$\oint {\overrightarrow E \,.\,d\overrightarrow l = - {{d{\phi _B}} \over {dt}}} $$
B. Faraday's Law II. $$\oint {\overrightarrow B \,.\,d\overrightarrow A = 0} $$
C. Gauss's Law in Magnetism III. $$\oint {\overrightarrow B \,.\,d\overrightarrow l = {\mu _0}{i_c} + {\mu _0}{ \in _0}{{d{\phi _E}} \over {dt}}} $$
D. Ampere-Maxwell Law IV. $$\oint {\overrightarrow E \,.\,d\overrightarrow s = {q \over {{ \in _0}}}} $$

Choose the correct answer from the options given below :

A
A-I, B-II, C-III, D-IV
B
A-III, B-IV, C-I, D-II
C
A-IV, B-I, C-II, D-III
D
A-II, B-III, C-IV, D-I
3
JEE Main 2023 (Online) 25th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An electromagnetic wave is transporting energy in the negative $$z$$ direction. At a certain point and certain time the direction of electric field of the wave is along positive $$y$$ direction. What will be the direction of the magnetic field of the wave at that point and instant?

A
Negative direction of $$y$$
B
Positive direction of $$z$$
C
Positive direction of $$x$$
D
Negative direction $$x$$
4
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$

$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$

Then the correct relation between E$$_0$$ and B$$_0$$ is given by

A
$$\mathrm{{E_o}{B_o} = \omega k}$$
B
$$\mathrm{{E_0} = k{B_0}}$$
C
$$\mathrm{k{E_0} = \omega {B_0}}$$
D
$$\mathrm{\omega {E_0} = k{B_0}}$$
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