JEE Main 2023 (Online) 29th January Morning Shift | Electromagnetic Waves Question 40 | Physics

1

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

+4

-1

Which of the following are true?

A. Speed of light in vacuum is dependent on the direction of propagation.

B. Speed of light in a medium is independent of the wavelength of light.

C. The speed of light is independent of the motion of the source.

D. The speed of light in a medium is independent of intensity.

Choose the correct answer from the options given below:

A

B and D only

B

B and C only

C

A and C only

D

C and D only

2

JEE Main 2023 (Online) 25th January Evening Shift

MCQ (Single Correct Answer)

+4

-1

Match List I with List II

	List I		List II
A.	Gauss's Law in Electrostatics	I.	$$\oint {\overrightarrow E \,.\,d\overrightarrow l = - {{d{\phi _B}} \over {dt}}} $$
B.	Faraday's Law	II.	$$\oint {\overrightarrow B \,.\,d\overrightarrow A = 0} $$
C.	Gauss's Law in Magnetism	III.	$$\oint {\overrightarrow B \,.\,d\overrightarrow l = {\mu _0}{i_c} + {\mu _0}{ \in _0}{{d{\phi _E}} \over {dt}}} $$
D.	Ampere-Maxwell Law	IV.	$$\oint {\overrightarrow E \,.\,d\overrightarrow s = {q \over {{ \in _0}}}} $$

Choose the correct answer from the options given below :

A

A-I, B-II, C-III, D-IV

B

A-III, B-IV, C-I, D-II

C

A-IV, B-I, C-II, D-III

D

A-II, B-III, C-IV, D-I

3

JEE Main 2023 (Online) 25th January Morning Shift

MCQ (Single Correct Answer)

+4

-1

An electromagnetic wave is transporting energy in the negative $$z$$ direction. At a certain point and certain time the direction of electric field of the wave is along positive $$y$$ direction. What will be the direction of the magnetic field of the wave at that point and instant?

A

Negative direction of $$y$$

B

Positive direction of $$z$$

C

Positive direction of $$x$$

D

Negative direction $$x$$

4

JEE Main 2023 (Online) 24th January Evening Shift

MCQ (Single Correct Answer)

+4

-1

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$

$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$

Then the correct relation between E$$_0$$ and B$$_0$$ is given by

A

$$\mathrm{{E_o}{B_o} = \omega k}$$

B

$$\mathrm{{E_0} = k{B_0}}$$

C

$$\mathrm{k{E_0} = \omega {B_0}}$$

D

$$\mathrm{\omega {E_0} = k{B_0}}$$