1
JEE Main 2026 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

\text { Match the LIST-I with LIST-II }

List-I List-II
A. Radio-wave I. is produced by Magnetron valve
B. Micro-wave II. due to change in the vibrational modes of atoms
C. Infrared-wave III. due to inner shell electrons moving from higher energy level to lower energy level
D. X-ray IV. due to rapid acceleration of electrons

Choose the correct answer from the options given below:

A

A-IV, B-II, C-I, D-III

B

A-IV, B-III, C-I, D-II

C

A-IV, B-I, C-II, D-III

D

A-II, B-IV, C-III, D-I

2
JEE Main 2026 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The ratio of speeds of electromagnetic waves in vacuum and a medium, having dielectric constant $k=3$ and permeability of $\mu=2 \mu_0$, is ( $\mu_0=$ permeability of vacuum)

A

$6: 1$

B

$3: 2$

C

$\sqrt{6}: 1$

D

$36: 1$

3
JEE Main 2026 (Online) 23rd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text { Match List - I with List - II. } $$

List - I
Relation
List - II
Law
A. $$
\oint \vec{E} \cdot \overrightarrow{d l}=-\frac{d}{d t} \oint \vec{B} \cdot \overrightarrow{d a}
$$
I. Ampere's circuital law
B. $$
\oint \vec{B} \cdot \overrightarrow{d l}=\mu_0\left(I+\epsilon_0 \frac{d \phi_E}{d t}\right)
$$
II. Faraday's laws of electromagnetic induction
C. $$
\oint \vec{E} \cdot \overrightarrow{d a}=\frac{1}{\epsilon_0} \int_{\mathrm{v}} \rho \mathrm{dv}
$$
III. Ampere - Maxwell law
D. $$
\oint \vec{B} \cdot \overrightarrow{d l}=\mu_0 I
$$
IV. Gauss's law of electrostatics

Choose the correct answer from the options given below :

A

A-I, B-IV, C-III, D-II

B

A-II, B-III, C-IV, D-I

C

A-IV, B-I, C-II, D-III

D

A-II, B-III, C-I, D-IV

4
JEE Main 2026 (Online) 22nd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A laser beam has intensity of $4.0 \times 10^{14} \mathrm{~W} / \mathrm{m}^2$. The amplitude of magnetic field associated with beam is $\_\_\_\_$ T.

(Take $\epsilon_{\mathrm{o}}=8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2$ and $\mathrm{c}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ )

A

1.83

B

2.0

C

5.5

D

18.3

JEE Main Subjects

Browse all chapters by subject