1
JEE Main 2022 (Online) 26th July Evening Shift
+4
-1

The oscillating magnetic field in a plane electromagnetic wave is given by

$$B_{y}=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^{8} t\right) T$$. The amplitude of electric field will be :

A
$$15 \times 10^{2} \,\mathrm{Vm}^{-1}$$
B
$$5 \times 10^{-6} \,\mathrm{Vm}^{-1}$$
C
$$16 \times 10^{12} \,\mathrm{Vm}^{-1}$$
D
$$4 \times 10^{2} \,\mathrm{Vm}^{-1}$$
2
JEE Main 2022 (Online) 26th July Evening Shift
+4
-1

A velocity selector consists of electric field $$\vec{E}=E \,\hat{k}$$ and magnetic field $$\vec{B}=B \,\hat{j}$$ with $$B=12 \,m T$$. The value of $$E$$ required for an electron of energy $$728 \,\mathrm{e} V$$ moving along the positive $$x$$-axis to pass undeflected is :

(Given, mass of electron $$=9.1 \times 10^{-31} \mathrm{~kg}$$ )

A
$$192 \,\mathrm{kVm}^{-1}$$
B
$$192 \,\mathrm{mVm}^{-1}$$
C
$$9600 \,\mathrm{kVm}^{-1}$$
D
$$16 \,\mathrm{kVm}^{-1}$$
3
JEE Main 2022 (Online) 26th July Morning Shift
+4
-1

The magnetic field of a plane electromagnetic wave is given by :

$$\overrightarrow{\mathrm{B}}=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \,\hat{j} \mathrm{~T}$$.

The amplitude of the electric field would be :

A
$$6\, \mathrm{Vm}^{-1}$$ along $$x$$-axis
B
$$3\, \mathrm{Vm}^{-1}$$ along $$z$$-axis
C
$$6\, \mathrm{Vm}^{-1}$$ along $$z$$-axis
D
$$2 \times 10^{-8} \,\mathrm{Vm}^{-1}$$ along $$z$$-axis
4
JEE Main 2022 (Online) 25th July Evening Shift
+4
-1

Light wave travelling in air along x-direction is given by $${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$$. Then, the peak value of magnetic field of wave will be (Given c = 3 $$\times$$ 108 ms$$-$$1)

A
18 $$\times$$ 10$$-$$7 T
B
54 $$\times$$ 10$$-$$7 T
C
54 $$\times$$ 10$$-$$8 T
D
18 $$\times$$ 10$$-$$8 T
EXAM MAP
Medical
NEET