1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A plane polarized monochromatic EM wave is traveling in vacuum along z direction such that at t = t1 it is found that the electric field is zero at a spatial point z1. The next zero that occurs in its neighbourhood is at z2. The frequency of the electroagnetic wave is :
A
$${{3 \times {{10}^8}} \over {\left| {{z_2} - {z_1}} \right|}}$$
B
$${{1.5 \times {{10}^8}} \over {\left| {{z_2} - {z_1}} \right|}}$$
C
$${{6 \times {{10}^8}} \over {\left| {{z_2} - {z_1}} \right|}}$$
D
$${1 \over {{t_1} + {{\left| {{z_2} - {z_1}} \right|} \over {3 \times {{10}^8}}}}}$$
2
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A monochromatic beam of light has a frequency $$v = {3 \over {2\pi }} \times {10^{12}}Hz$$ and is propagating along the direction $${{\widehat i + \widehat j} \over {\sqrt 2 }}.$$
It is polarized along the $$\widehat k$$ direction. The acceptable form for the magnetic field is :
A
JEE Main 2018 (Online) 15th April Morning Slot Physics - Electromagnetic Waves Question 130 English Option 1
B
JEE Main 2018 (Online) 15th April Morning Slot Physics - Electromagnetic Waves Question 130 English Option 2
C
JEE Main 2018 (Online) 15th April Morning Slot Physics - Electromagnetic Waves Question 130 English Option 3
D
JEE Main 2018 (Online) 15th April Morning Slot Physics - Electromagnetic Waves Question 130 English Option 4
3
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The electric field component of a monochromatic radiation is given by

$$\overrightarrow E $$ = 2 E0 $$\widehat i$$ cos kz cos $$\omega $$t

Its magnetic field $$\overrightarrow B $$ is then given by :
A
$${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz cos $$\omega $$t
B
$$-$$ $${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz sin $$\omega $$t
C
$${{2{E_0}} \over c}$$ $$\widehat j$$ sin kz sin $$\omega $$t
D
$${{2{E_0}} \over c}$$ $$\widehat j$$ cos kz cos $$\omega $$t
4
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Magnetic field in a plane electromagnetic wave is given by

$$\overrightarrow B $$ = B0 sin (k x + $$\omega $$t) $$\widehat j\,T$$

Expression for corresponding electric field will be :
Where c is speed of light.
A
$$\overrightarrow E $$ = B0 c sin (k x + $$\omega $$t) $$\widehat k$$ V/m
B
$$\overrightarrow E $$ = $${{{B_0}} \over c}$$ sin (k x + $$\omega $$t) $$\widehat k$$ V/m
C
$$\overrightarrow E $$ = $$-$$ B0 c sin (kx +$$\omega $$t) $$\widehat k$$ V/m
D
$$\overrightarrow E $$ = B0 c sin (kx $$-$$$$\omega $$t) $$\widehat k$$ V/m
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