JEE Main 2020 (Online) 5th September Evening Slot | Dual Nature of Radiation Question 67 | Physics

JEE Main 2020 (Online) 5th September Evening Slot

MCQ (Single Correct Answer)

-1

The correct match between the entries in column I and column II are :

I	II
Radiation	Wavelength
(a) Microwave	(i) 100 m
(b) Gamma rays	(ii) 10^–15 m
(c) A.M. radio waves	(iii) 10^–10 m
(d) X-rays	(iv) 10^–3 m

(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)

(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)

(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

Find the Binding energy per neucleon for $${}_{50}^{120}Sn$$. Mass of proton m_p = 1.00783 U, mass of neutron m_n = 1.00867 U and mass of tin nucleus m_Sn = 119.902199 U. (take 1U = 931 MeV)

9.0 MeV

8.5 MeV

8.0 MeV

7.5 MeV

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased : JEE Main 2020 (Online) 4th September Evening Slot Physics - Dual Nature of Radiation Question 68 English

JEE Main 2020 (Online) 4th September Evening Slot Physics - Dual Nature of Radiation Question 68 English

Slope of the straight line get more steep

Graph does not change

Straight line shifts to left

Straight line shifts to right

JEE Main 2020 (Online) 4th September Morning Slot

MCQ (Single Correct Answer)

-1

Particle A of mass m_A = $${m \over 2}$$ moving along the x-axis with velocity v₀ collides elastically with another particle B at rest having mass m_B = $${m \over 3}$$. If both particles move along the x-axis after the collision, the change $$\Delta $$$$\lambda $$ in de-Broglie wavlength of particle A, in terms of its de-Broglie wavelength ($$\lambda $$₀) before collision is :

$$\Delta $$$$\lambda $$ = $${5 \over 2}{\lambda _0}$$

$$\Delta $$$$\lambda $$ = $${3 \over 2}{\lambda _0}$$

$$\Delta $$$$\lambda $$ = 2$$\lambda $$₀

$$\Delta $$$$\lambda $$ = 4$$\lambda $$₀

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