1
JEE Main 2020 (Online) 5th September Evening Slot
+4
-1
The correct match between the entries in column I and column II are :

I II
(a) Microwave (i) 100 m
(b) Gamma rays (ii) 10–15 m
(c) A.M. radio waves (iii) 10–10 m
(d) X-rays (iv) 10–3 m
A
(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
B
(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
C
(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
D
(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
2
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
Find the Binding energy per neucleon for $${}_{50}^{120}Sn$$. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV)
A
9.0 MeV
B
8.5 MeV
C
8.0 MeV
D
7.5 MeV
3
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased :
A
Slope of the straight line get more steep
B
Graph does not change
C
Straight line shifts to left
D
Straight line shifts to right
4
JEE Main 2020 (Online) 4th September Morning Slot
+4
-1
Particle A of mass mA = $${m \over 2}$$ moving along the x-axis with velocity v0 collides elastically with another particle B at rest having mass mB = $${m \over 3}$$. If both particles move along the x-axis after the collision, the change $$\Delta$$$$\lambda$$ in de-Broglie wavlength of particle A, in terms of its de-Broglie wavelength ($$\lambda$$0) before collision is :
A
$$\Delta$$$$\lambda$$ = $${5 \over 2}{\lambda _0}$$
B
$$\Delta$$$$\lambda$$ = $${3 \over 2}{\lambda _0}$$
C
$$\Delta$$$$\lambda$$ = 2$$\lambda$$0
D
$$\Delta$$$$\lambda$$ = 4$$\lambda$$0
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