1
JEE Main 2022 (Online) 26th July Morning Shift
+4
-1

The magnetic field of a plane electromagnetic wave is given by :

$$\overrightarrow{\mathrm{B}}=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \,\hat{j} \mathrm{~T}$$.

The amplitude of the electric field would be :

A
$$6\, \mathrm{Vm}^{-1}$$ along $$x$$-axis
B
$$3\, \mathrm{Vm}^{-1}$$ along $$z$$-axis
C
$$6\, \mathrm{Vm}^{-1}$$ along $$z$$-axis
D
$$2 \times 10^{-8} \,\mathrm{Vm}^{-1}$$ along $$z$$-axis
2
JEE Main 2022 (Online) 25th July Evening Shift
+4
-1

Light wave travelling in air along x-direction is given by $${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$$. Then, the peak value of magnetic field of wave will be (Given c = 3 $$\times$$ 108 ms$$-$$1)

A
18 $$\times$$ 10$$-$$7 T
B
54 $$\times$$ 10$$-$$7 T
C
54 $$\times$$ 10$$-$$8 T
D
18 $$\times$$ 10$$-$$8 T
3
JEE Main 2022 (Online) 25th July Morning Shift
+4
-1

The rms value of conduction current in a parallel plate capacitor is $$6.9 \,\mu \mathrm{A}$$. The capacity of this capacitor, if it is connected to $$230 \mathrm{~V}$$ ac supply with an angular frequency of $$600 \,\mathrm{rad} / \mathrm{s}$$, will be :

A
5 pF
B
50 pF
C
100 pF
D
200 pF
4
JEE Main 2022 (Online) 30th June Morning Shift
+4
-1

An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5$$\pi$$ $$\times$$ 103x $$-$$ 3$$\pi$$ $$\times$$ 1011t) Vm$$-$$1

Then, the value of magnetic field amplitude will be :

(Given : speed of light in Vacuum c = 3 $$\times$$ 108 ms$$-$$1)

A
1 $$\times$$ 10$$-$$6 T
B
5 $$\times$$ 10$$-$$6 T
C
18 $$\times$$ 109 T
D
21 $$\times$$ 109 T
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