This chapter is currently out of syllabus
1
JEE Main 2021 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
If in a triangle ABC, AB = 5 units, $$\angle B = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)$$ and radius of circumcircle of $$\Delta$$ABC is 5 units, then the area (in sq. units) of $$\Delta$$ABC is :
A
$$10 + 6\sqrt 2 $$
B
$$8 + 2\sqrt 2 $$
C
$$6 + 8\sqrt 3 $$
D
$$4 + 2\sqrt 3 $$
2
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The triangle of maximum area that can be inscribed in a given circle of radius 'r' is :
A
An equilateral triangle having each of its side of length $$\sqrt 3 $$r.
B
An equilateral triangle of height $${{2r} \over 3}$$.
C
A right angle triangle having two of its sides of length 2r and r.
D
An isosceles triangle with base equal to 2r.
3
JEE Main 2021 (Online) 24th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, c), (2, b) and (a, b) be $$\left( {{{10} \over 3},{7 \over 3}} \right)$$. If $$\alpha$$, $$\beta$$ are the roots of the equation $$a{x^2} + bx + 1 = 0$$, then the value of $${\alpha ^2} + {\beta ^2} - \alpha \beta $$ is :
A
$${{69} \over {256}}$$
B
$${{71} \over {256}}$$
C
$$ - {{71} \over {256}}$$
D
$$ - {{69} \over {256}}$$
4
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If $$\angle BAC = {90^o}$$ and area$$\left( {\Delta ABC} \right) = 5\sqrt 5 $$ s units, then the abscissa of the vertex C is :
A
$$1 + 2\sqrt 5 $$
B
$$ 2\sqrt 5 - 1$$
C
$$1 + \sqrt 5 $$
D
$$2 + \sqrt 5 $$
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