1
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
Given $${{b + c} \over {11}} = {{c + a} \over {12}} = {{a + b} \over {13}}$$ for a $$\Delta$$ABC with usual notation.

If   $${{\cos A} \over \alpha } = {{\cos B} \over \beta } = {{\cos C} \over \gamma },$$ then the ordered triad ($$\alpha$$, $$\beta$$, $$\gamma$$) has a value :
A
(19, 7, 25)
B
(7, 19, 25)
C
(5, 12, 13)
D
(3, 4, 5)
2
JEE Main 2019 (Online) 11th January Morning Slot
+4
-1
In a triangle, the sum of lengths of two sides is x and the product of the lengths of the same two sides is y. If x2 – c2 = y, where c is the length of the third side of the triangle, then the circumradius of the triangle is :
A
$${y \over {\sqrt 3 }}$$
B
$${c \over 3}$$
C
$${c \over {\sqrt 3 }}$$
D
$${3 \over 2}$$y
3
JEE Main 2019 (Online) 10th January Evening Slot
+4
-1
With the usual notation, in $$\Delta$$ABC, if $$\angle A + \angle B$$ = 120o, a = $$\sqrt 3$$ $$+$$ 1, b = $$\sqrt 3$$ $$-$$ 1 then the ratio $$\angle A:\angle B,$$ is :
A
9 : 7
B
7 : 1
C
5 : 3
D
3 : 1
4
JEE Main 2018 (Offline)
+4
-1
Let the orthocentre and centroid of a triangle be A(-3, 5) and B(3, 3) respectively. If C is the circumcentre of this triangle, then the radius of the circle having line segment AC as diameter, is :
A
$${{3\sqrt 5 } \over 2}$$
B
$$\sqrt {10}$$
C
$$2\sqrt {10}$$
D
$$3\sqrt {{5 \over 2}}$$
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