AIEEE 2003 | Electrochemistry Question 199 | Chemistry

For the redox reaction Zn(s) + Cu²⁺(0.1 M) $$\to$$ Zn²⁺(1M) + Cu(s) taking place in a cell, $$E_{cell}^o$$ is 1.10 volt. E_cell for the cell will be ($$2.303{{RT} \over F}$$ = 0.0591)

1.80 volt

1.07 volt

0.82 volt

2.14 volt

AIEEE 2002

MCQ (Single Correct Answer)

-1

Conductivity (Seimen’s S) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then, then constant of proportionality is expressed in :

Sm mol^-1

Sm² mol^-1

S^-2m² mol

S²m² mol^-2

AIEEE 2002

MCQ (Single Correct Answer)

-1

For the following cell with hydrogen electrodes at two different pressure p₁ and p₂. What will be the emf for the given cell :

$$\eqalign{ & Pt({H_2})|{H^ + }(aq)|Pt({H_2}) \cr & \,\,\,\,\,{p_1}\,\,\,\,\,\,\,\,\,\,\,\,\,\,1M\,\,\,\,\,\,\,\,\,\,\,\,{p_2} \cr} $$

$${{RT} \over F}{\log _e}{{{P_1}} \over {{P_2}}}$$

$${{RT} \over 2F}{\log _e}{{{P_1}} \over {{P_2}}}$$

$${{RT} \over F}{\log _e}{{{P_2}} \over {{P_1}}}$$

none of these

AIEEE 2002

MCQ (Single Correct Answer)

-1

EMF of a cell in terms of reduction potential of its left and right electrodes is :

E = E_left - E_right

E = E_left + E_right

E = E_right - E_left

E = -(E_right + E_left)