1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
An NPN transistor is used in common emitter configuration as an amplifier with 1 k$$\Omega $$ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15μA change in the base current of the amplifier. The input resistance and voltage gain are :
A
0.67 kW, 200
B
0.33 kW, 1.5
C
0.67 kW, 300
D
0.33 kW, 300
2
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC = 1k$$\Omega$$ and VCC = 10 V. What is the minimum base current for VCE to reach saturation ? JEE Main 2019 (Online) 8th April Evening Slot Physics - Semiconductor Question 134 English
A
100 $$\mu $$A
B
7 $$\mu $$A
C
10 $$\mu $$A
D
40 $$\mu $$A
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit.

The current IZ through the Zener is : JEE Main 2019 (Online) 8th April Morning Slot Physics - Semiconductor Question 135 English
A
7 mA
B
17 mA
C
15mA
D
10 mA
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC = 5V, $$\beta $$dc = 200, RB = 100 k$$\Omega $$, RC = 1 k$$\Omega $$ and VBE = 1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be respectively :

JEE Main 2019 (Online) 12th January Evening Slot Physics - Semiconductor Question 136 English
A
20 $$\mu $$A and 2.8 V
B
25 $$\mu $$A and 2.8 V
C
20 $$\mu $$A and 3.5 V
D
25 $$\mu $$A and 3.5 V
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