1
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Out of Syllabus
An NPN transistor is used in common emitter configuration as an amplifier with 1 k$$\Omega$$ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15μA change in the base current of the amplifier. The input resistance and voltage gain are :
A
0.67 kW, 200
B
0.33 kW, 1.5
C
0.67 kW, 300
D
0.33 kW, 300
2
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
Out of Syllabus
A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC = 1k$$\Omega$$ and VCC = 10 V. What is the minimum base current for VCE to reach saturation ?
A
100 $$\mu$$A
B
7 $$\mu$$A
C
10 $$\mu$$A
D
40 $$\mu$$A
3
JEE Main 2019 (Online) 8th April Morning Slot
+4
-1
The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit.

The current IZ through the Zener is :
A
7 mA
B
17 mA
C
15mA
D
10 mA
4
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
Out of Syllabus
In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC = 5V, $$\beta$$dc = 200, RB = 100 k$$\Omega$$, RC = 1 k$$\Omega$$ and VBE = 1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be respectively :

A
20 $$\mu$$A and 2.8 V
B
25 $$\mu$$A and 2.8 V
C
20 $$\mu$$A and 3.5 V
D
25 $$\mu$$A and 3.5 V
EXAM MAP
Medical
NEET