1
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
The truth table for the circuit given in the fig. is:
A
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$
B
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 0 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
C
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
D
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 0 \cr 0 & 1 & 0 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$
2
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
Out of Syllabus
The transfer characteristic curve of a transistor, having input and output resistance 100 $$\Omega$$ and 100 k$$\Omega$$ respectively is shown in the figure. The voltage and power gain, are respectively:
A
5 × 104, 5 × 105
B
5 × 104, 5 × 106
C
5 × 104, 2.5 × 106
D
2.5 × 104, 2.5 × 106
3
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is 6 V and the load resistance is, RL = 4k$$\Omega$$. The series resistance of the circuit is Ri = 1 k$$\Omega$$. If the battery voltage VB varies from 8 V to 16 V, what are the minimum and maximum values of the current through Zener diode?
A
0.5 mA; 8.5 mA
B
1.5 mA; 8.5 mA
C
1 mA; 8.5 mA
D
0.5 mA; 6 mA
4
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
Out of Syllabus
An n-p-n transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100$$\Omega$$ and the output load resistance is 10 k$$\Omega$$. The common emitter current gain $$\beta$$ is :
A
104
B
102
C
6 × 102
D
60
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