1
JEE Main 2018 (Online) 16th April Morning Slot
+4
-1
In the given circuit, the current through zener diode is :

A
5.5 mA
B
6.7 mA
C
2.5 mA
D
3.3 mA
2
JEE Main 2018 (Offline)
+4
-1
The reading of the ammeter for a silicon diode in the given circuit is :
A
13.5 mA
B
0
C
15 mA
D
11.5 mA
3
JEE Main 2018 (Online) 15th April Evening Slot
+4
-1
Truth table for the following digital circuit will be :
A
B
C
D
4
JEE Main 2018 (Online) 15th April Morning Slot
+4
-1
In a common emitter configuration with suitable bias, it is given that $${R_L}$$ is the load resistance and $${R_{BE}}$$ is small signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by :

$$\beta$$ is curret gain, $${{\rm I}_B},{{\rm I}_C}$$ and $${{\rm I}_E}$$ are respectively base, collector and emitter currents.
A
$$\beta {{{R_L}} \over {{R_{BE}}}},{{\Delta {{\rm I}_C}} \over {\Delta {{\rm I}_B}}},{\beta ^2}{{{R_L}} \over {{R_{BE}}}}$$
B
$$\beta {{{R_L}} \over {{R_{BE}}}},{{\Delta {{\rm I}_E}} \over {\Delta {{\rm I}_B}}},{\beta ^2}{{{R_L}} \over {{R_{BE}}}}$$
C
$${\beta ^2}{{{R_L}} \over {{R_{BE}}}},{{\Delta {{\rm I}_C}} \over {\Delta {{\rm I}_E}}},{\beta ^2}{{{R_L}} \over {{R_{BE}}}}$$
D
$${\beta ^2}{{{R_L}} \over {{R_{BE}}}},{{\Delta {{\rm I}_C}} \over {\Delta {{\rm I}_B}}},\beta {{{R_L}} \over {{R_{BE}}}}$$
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