JEE Main 2019 (Online) 9th April Evening Slot | Semiconductor Question 144 | Physics

An NPN transistor is used in common emitter configuration as an amplifier with 1 k$$\Omega $$ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15μA change in the base current of the amplifier. The input resistance and voltage gain are :

0.67 kW, 200

0.33 kW, 1.5

0.67 kW, 300

0.33 kW, 300

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, R_C = 1k$$\Omega$$ and V_CC = 10 V. What is the minimum base current for V_CE to reach saturation ? JEE Main 2019 (Online) 8th April Evening Slot Physics - Semiconductor Question 146 English

JEE Main 2019 (Online) 8th April Evening Slot Physics - Semiconductor Question 146 English

100 $$\mu $$A

7 $$\mu $$A

10 $$\mu $$A

40 $$\mu $$A

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit.

The current IZ through the Zener is : JEE Main 2019 (Online) 8th April Morning Slot Physics - Semiconductor Question 147 English