1
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100$$\Omega$$ and the output load resistance is 10 k$$\Omega$$. The common emitter current gain $$\beta$$ is :
A
104
B
102
C
6 × 102
D
60
2
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
The logic gate equivalent to the given logic circuit is :-
A
NAND
B
AND
C
NOR
D
OR
3
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
An NPN transistor is used in common emitter configuration as an amplifier with 1 k$$\Omega$$ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15μA change in the base current of the amplifier. The input resistance and voltage gain are :
A
0.67 kW, 200
B
0.33 kW, 1.5
C
0.67 kW, 300
D
0.33 kW, 300
4
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC = 1k$$\Omega$$ and VCC = 10 V. What is the minimum base current for VCE to reach saturation ?
A
100 $$\mu$$A
B
7 $$\mu$$A
C
10 $$\mu$$A
D
40 $$\mu$$A
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