JEE Main 2025 (Online) 2nd April Evening Shift | Semiconductor Question 8 | Physics | JEE Main - ExamSIDE.com

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1

JEE Main 2025 (Online) 2nd April Evening Shift

MCQ (Single Correct Answer)

+4

-1

$$ \text { In the digital circuit shown in the figure, for the given inputs the } P \text { and } Q \text { values are : } $$

JEE Main 2025 (Online) 2nd April Evening Shift Physics - Semiconductor Question 7 English

A

$P=0, Q=1$

B

$P=1, Q=0$

C

$\mathrm{P}=0, \mathrm{Q}=0$

D

$P=1, Q=1$

2

JEE Main 2025 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

+4

-1

A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V . For a $400 \Omega$ resistor connected in series, the zener current is found to be 4 times load current. The load current $\left(I_L\right)$ and load resistance $\left(R_L\right)$ are :

A

$\mathrm{I}_{\mathrm{L}}=0.02 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=250 \Omega$

B

$\mathrm{I}_{\mathrm{L}}=10 \mathrm{~A} ; \mathrm{R}_{\mathrm{L}}=0.5 \Omega$

C

$\mathrm{I}_{\mathrm{L}}=10 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=500 \Omega$

D

$\mathrm{I}_{\mathrm{L}}=20 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=250 \Omega$

3

JEE Main 2025 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

+4

-1

The truth table for the circuit given below is:

JEE Main 2025 (Online) 29th January Evening Shift Physics - Semiconductor Question 17 English

A

A	B	Y
0	0	0
1	1	1
1	0	1
0	1	1

B

A	B	Y
0	0	0
1	0	1
0	1	0
1	1	0

C

A	B	Y
0	0	0
1	0	0
1	1	0
0	1	1

D

A	B	Y
0	0	0
0	1	1
1	0	1
1	1	0

4

JEE Main 2025 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

+4

-1

JEE Main 2025 (Online) 29th January Morning Shift Physics - Semiconductor Question 18 English

For the circuit shown above, equivalent GATE is :

A

NOT gate

B

NAND gate

C

AND gate

D

OR gate

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