1
JEE Main 2025 (Online) 2nd April Evening Shift
MCQ (Single Correct Answer)
+4
-1

$$ \text { In the digital circuit shown in the figure, for the given inputs the } P \text { and } Q \text { values are : } $$

JEE Main 2025 (Online) 2nd April Evening Shift Physics - Semiconductor Question 7 English
A
$P=0, Q=1$
B
$P=1, Q=0$
C
$\mathrm{P}=0, \mathrm{Q}=0$
D
$P=1, Q=1$
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V . For a $400 \Omega$ resistor connected in series, the zener current is found to be 4 times load current. The load current $\left(I_L\right)$ and load resistance $\left(R_L\right)$ are :

A
$\mathrm{I}_{\mathrm{L}}=0.02 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=250 \Omega$
B
$\mathrm{I}_{\mathrm{L}}=10 \mathrm{~A} ; \mathrm{R}_{\mathrm{L}}=0.5 \Omega$
C
$\mathrm{I}_{\mathrm{L}}=10 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=500 \Omega$
D
$\mathrm{I}_{\mathrm{L}}=20 \mathrm{~mA} ; \mathrm{R}_{\mathrm{L}}=250 \Omega$
3
JEE Main 2025 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The truth table for the circuit given below is:

JEE Main 2025 (Online) 29th January Evening Shift Physics - Semiconductor Question 17 English
A
ABY
000
111
101
011
B
ABY
000
101
010
110
C
ABY
000
100
110
011
D
ABY
000
011
101
110
4
JEE Main 2025 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
JEE Main 2025 (Online) 29th January Morning Shift Physics - Semiconductor Question 18 English

For the circuit shown above, equivalent GATE is :

A

NOT gate

B

NAND gate

C

AND gate

D

OR gate

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