1
JEE Main 2025 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Preparation of potassium permanganate from $\mathrm{MnO}_2$ involves two step process in which the 1st step is a reaction with KOH and $\mathrm{KNO}_3$ to produce

A
$\mathrm{K}_3 \mathrm{MnO}_4$
B
$\mathrm{K}_4\left[\mathrm{Mn}(\mathrm{OH})_6\right]$
C
$\mathrm{K}_2 \mathrm{MnO}_4$
D
$\mathrm{KMnO}_4$
2
JEE Main 2025 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which one of the carbocations from the following is most stable?

A
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Basics of Organic Chemistry Question 22 English Option 1
B
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Basics of Organic Chemistry Question 22 English Option 2
C
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Basics of Organic Chemistry Question 22 English Option 3
D
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Basics of Organic Chemistry Question 22 English Option 4
3
JEE Main 2025 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The product $(\mathrm{A})$ formed in the following reaction sequence is

JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Hydrocarbons Question 7 English

A
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Hydrocarbons Question 7 English Option 1
B
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Hydrocarbons Question 7 English Option 2
C
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Hydrocarbons Question 7 English Option 3
D
JEE Main 2025 (Online) 24th January Morning Shift Chemistry - Hydrocarbons Question 7 English Option 4
4
JEE Main 2025 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$\mathrm{K}_{\mathrm{sp}}$ for $\mathrm{Cr}(\mathrm{OH})_3$ is $1.6 \times 10^{-30}$. What is the molar solubility of this salt in water?

A
$\sqrt[5]{1.8 \times 10^{-30}}$
B
$\frac{1.8 \times 10^{-30}}{27}$
C
$\sqrt[4]{\frac{1.6 \times 10^{-30}}{27}}$
D
$\sqrt[2]{1.6 \times 10^{-30}}$
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