1
JEE Main 2024 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The correct set of four quantum numbers for the valence electron of rubidium atom $$(\mathrm{Z}=37)$$ is :

A
$$5,1,1,+\frac{1}{2}$$
B
$$5,0,0,+\frac{1}{2}$$
C
$$5,0,1,+\frac{1}{2}$$
D
$$5,1,0,+\frac{1}{2}$$
2
JEE Main 2024 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The difference in energy between the actual structure and the lowest energy resonance structure for the given compound is

A
electromeric energy
B
resonance energy
C
ionization energy
D
hyperconjugation energy
3
JEE Main 2024 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

List - I
(Substances)
List - II
(Element Present)
(A) Ziegler catalyst (I) Rhodium
(B) Blood Pigment (II) Cobalt
(C) Wilkinson catalyst (III) Iron
(D) Vitamin $$\mathrm{B_{12}}$$ (IV) Titanium

Choose the correct answer from the options given below:

A
A-IV, B-III, C-I, D-II
B
A-II, B-IV, C-I, D-III
C
A-III, B-II, C-IV, D-I
D
A-II, B-III, C-IV, D-I
4
JEE Main 2024 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The final product A formed in the following multistep reaction sequence is

JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 13 English

A
JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 13 English Option 1
B
JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 13 English Option 2
C
JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 13 English Option 3
D
JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 13 English Option 4
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