1
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
In acidic medium, $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ shows oxidising action as represented in the half reaction:

$$ \mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}+\mathrm{XH}^{+}+\mathrm{Ye}^{\ominus} \rightarrow 2 \mathrm{~A}+\mathrm{ZH}_2 \mathrm{O} $$

$\mathrm{X}, \mathrm{Y}, \mathrm{Z}$ and $\mathrm{A}$ are respectively are :
A
$14,7,6$ and $\mathrm{Cr}^{3+}$
B
$14,6,7$ and $\mathrm{Cr}^{3+}$
C
$8,4,6$ and $\mathrm{Cr}_2 \mathrm{O}_3$
D
$8,6,4$ and $\mathrm{Cr}_2 \mathrm{O}_3$
2
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Given below are two statements :

Statement (I) : Aminobenzene and aniline are same organic compounds.

Statement (II) : Aminobenzene and aniline are different organic compounds.

In the light of the above statements, choose the most appropriate answer from the options given below :
A
Both Statement I and Statement II are correct
B
Statement I is incorrect but Statement II is correct
C
Statement I is correct but Statement II is incorrect
D
Both Statement I and Statement II are incorrect
3
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Match List - I with List - II.

List I (Reactions) List II (Reagents)
(A) JEE Main 2024 (Online) 1st February Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 29 English 1 (I) CH3MgBr, H2O
(B) C6H5COC6H5 ⟶ C6H5CH=C6H5 (II) Zn(Hg) and conc. HCl
(C) C6H5CHO ⟶ C6H5CH(OH)CH3 (III) NaBH4, H+
(D) JEE Main 2024 (Online) 1st February Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 29 English 2 (IV) DIBAL-H, H2O


Choose the correct answer from the options given below :
A
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
B
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
C
(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
D
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
4
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Arrange the bonds in order of increasing ionic character in the molecules. $\mathrm{LiF}$, $\mathrm{K}_2 \mathrm{O}, \mathrm{N}_2, \mathrm{SO}_2$ and $\mathrm{ClF}_3$ :
A
$\mathrm{N}_2<\mathrm{SO}_2<\mathrm{ClF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
B
$\mathrm{ClF}_3<\mathrm{N}_2<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
C
$\mathrm{LiF}<\mathrm{K}_2 \mathrm{O}<\mathrm{ClF}_3<\mathrm{SO}_2<\mathrm{N}_2$
D
$\mathrm{N}_2<\mathrm{ClF}_3<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
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