1
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
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The current voltage relation of diode is given by $${\rm I} = \left( {{e^{100V/T}} - 1} \right)mA,$$ where the applied voltage $$V$$ is in volts and the temperature $$T$$ is in degree kelvin. If a student makes an error measuring $$ \pm 0.01\,V$$ while measuring the current of $$5$$ $$mA$$ at $$300$$ $$K,$$ what will be the error in the value of current on $$mA$$?
A
$$0.2$$ $$mA$$
B
$$0.02$$ $$mA$$
C
$$0.5$$ $$mA$$
D
$$0.05$$ $$mA$$
2
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
In the circuit shown here, the point $$'C'$$ is kept connected to point $$'A'$$ till the current flowing through the circuit becomes constant. Afterward, suddenly, point $$'C'$$ is disconnected from point $$'A'$$ and connected to point $$'B'$$ at time $$t=0.$$ Ratio of the voltage across resistance and the inductor at $$t=L/R$$ will be equal to : JEE Main 2014 (Offline) Physics - Alternating Current Question 151 English
A
$${e \over {1 - e}}$$
B
$$1$$
C
$$-1$$
D
$${{1 - e} \over e}$$
3
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
A green light is incident from the water to the air - water interface at the critical angle $$\left( \theta \right)$$. Select the correct statement.
A
The entire spectrum of visible light will come out of the water at an angle of $${90^ \circ }$$ to the normal.
B
The spectrum of visible light whose frequency is less than that of green light will come out to the air medium.
C
The spectrum of visible light whose frequency is more than that of green light will come out to the air medium.
D
The entire spectrum of visible light will come out of the water at various angles to the normal.
4
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
Two beams, $$A$$ and $$B$$, of plane polarized light with mutually perpendicular planes of polarization are seen through a polaroid. From the position when the beam $$A$$ has maximum intensity (and beam $$B$$ has zero intensity), a rotation of polaroid through $${30^ \circ }$$ makes the two beams appear equally bright. If the initial intensities of the two beams are $${{\rm I}_A}$$ and $${{\rm I}_B}$$ respectively, then $${{{{\rm I}_A}} \over {{{\rm I}_B}}}$$ equals:
A
$$3$$
B
$${3 \over 2}$$
C
$$1$$
D
$${1 \over 3}$$
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