1
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
Let $$f_k\left( x \right) = {1 \over k}\left( {{{\sin }^k}x + {{\cos }^k}x} \right)$$ where $$x \in R$$ and $$k \ge \,1.$$
Then $${f_4}\left( x \right) - {f_6}\left( x \right)\,\,$$ equals :
A
$${1 \over 4}$$
B
$${1 \over 12}$$
C
$${1 \over 6}$$
D
$${1 \over 3}$$
2
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
The angle between the lines whose direction cosines satisfy the equations $$l+m+n=0$$ and $${l^2} = {m^2} + {n^2}$$ is :
A
$${\pi \over 6}$$
B
$${\pi \over 2}$$
C
$${\pi \over 3}$$
D
$${\pi \over 4}$$
3
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The current voltage relation of diode is given by $${\rm I} = \left( {{e^{100V/T}} - 1} \right)mA,$$ where the applied voltage $$V$$ is in volts and the temperature $$T$$ is in degree kelvin. If a student makes an error measuring $$ \pm 0.01\,V$$ while measuring the current of $$5$$ $$mA$$ at $$300$$ $$K,$$ what will be the error in the value of current on $$mA$$?
A
$$0.2$$ $$mA$$
B
$$0.02$$ $$mA$$
C
$$0.5$$ $$mA$$
D
$$0.05$$ $$mA$$
4
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
The forward biased diode connection is:
A
JEE Main 2014 (Offline) Physics - Semiconductor Question 170 English Option 1
B
JEE Main 2014 (Offline) Physics - Semiconductor Question 170 English Option 2
C
JEE Main 2014 (Offline) Physics - Semiconductor Question 170 English Option 3
D
JEE Main 2014 (Offline) Physics - Semiconductor Question 170 English Option 4
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