JEE Main 2025 (Online) 2nd April Evening Shift | Electrostatics Question 41 | Physics

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is V . The potential difference between the points A and $B$ (shown in the figure) is : JEE Main 2025 (Online) 2nd April Evening Shift Physics - Electrostatics Question 35 English

JEE Main 2025 (Online) 2nd April Evening Shift Physics - Electrostatics Question 35 English

1 V

$\frac{1}{4} \mathrm{~V}$

$\frac{3}{4} \mathrm{~V}$

$\frac{2}{5} \mathrm{~V}$

JEE Main 2025 (Online) 2nd April Evening Shift

MCQ (Single Correct Answer)

-1

Consider a circular loop that is uniformly charged and has a radius $\mathrm{a} \sqrt{2}$. Find the position along the positive $z$-axis of the cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in $x y$ plane at the origin :

$a / 2$

$$ a / \sqrt{2} $$

JEE Main 2025 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

-1

Consider two infinitely large plane parallel conducting plates as shown below. The plates are uniformly charged with a surface charge density $+\sigma$ and $-2 \sigma$. The force experienced by a point charge +q placed at the mid point between two plates will be:

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Electrostatics Question 40 English

$\frac{3 \sigma q}{4 \epsilon_0}$

$\frac{3 \sigma \mathrm{q}}{2 \epsilon_0}$

$\frac{\sigma \mathrm{q}}{4 \epsilon_0}$

$\frac{\sigma q}{2 \epsilon_0}$

JEE Main 2025 (Online) 2nd April Morning Shift

MCQ (Single Correct Answer)

-1

A point charge $+q$ is placed at the origin. A second point charge $+9 q$ is placed at ($\mathrm{d}, 0,0$) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

$(3 \mathrm{d} / 4,0,0)$

$(\mathrm{d} / 4,0,0)$

$(4 \mathrm{d} / 3,0,0)$

$(\mathrm{d} / 3,0,0)$

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