1
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match the LIST-I with LIST-II

LIST-I (Reagent)LIST-II (Functional Group detected)
A. Sodium bicarbonate solutionI. double bond/unsaturation
B. Neutral ferric chlorideII. carboxylic acid
C. ceric ammonium nitrateIII. phenolic - OH
D. alkaline KMnO4IV. alcoholic - OH

Choose the correct answer from the options given below:

A

A-II, B-III, C-I, D-IV

B

A-II, B-IV, C-III, D-I

C

A-III, B-II, C-IV, D-I

D

A-II, B-III, C-IV, D-I

2
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 5 English

Choose the correct option for structures of $A$ and $B$, respectively

A
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 5 English Option 1
B
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 5 English Option 2
C
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 5 English Option 3
D
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 5 English Option 4
3
JEE Main 2025 (Online) 8th April Evening Shift
Numerical
+4
-1

Consider the following half cell reaction

$$ \text{Cr}_2\text{O}_7^{2-} \, (\text{aq}) + 6\text{e}^- + 14\text{H}^+ \, (\text{aq}) \rightarrow 2\text{Cr}^{3+} \, (\text{aq}) + 7\text{H}_2\text{O} \, (\ell) $$

The reaction was conducted with the ratio of $$\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}$$. The pH value at which the EMF of the half cell will become zero is __________.

(nearest integer value)

[Given: standard half cell reduction potential $$E^{\circ}_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\, \text{V}$$, $$\frac{2.303RT}{F} = 0.059\, \text{V}$$.]

Your input ____
4
JEE Main 2025 (Online) 8th April Evening Shift
Numerical
+4
-1

The energy of an electron in the first Bohr orbit of the H-atom is -13.6 eV.

The magnitude of energy value of an electron in the first excited state of Be3+ is ________ eV (nearest integer value).

Your input ____
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