1
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The correct decreasing order of spin only magnetic moment values (BM) of Cu+, Cu2+, Cr2+ and Cr3+ ions is :

A

Cr3+ > Cr2+ > Cu+ > Cu2+

B

Cu+ > Cu2+ > Cr3+ > Cr2+

C

Cr2+ > Cr3+ > Cu2+ > Cu+

D

Cu2+ > Cu+ > Cr2+ > Cr3+

2
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements:

Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism.

Statement II: cis- and trans- platin are heteroleptic complexes of Pd.

In the light of the above statements, choose the correct answer from the options given below:

A

Statement I is true but Statement II is false

B

Both Statement I and Statement II are true

C

Both Statement I and Statement II are false

D

Statement I is false but Statement II is true

3
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
When JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English undergoes intramolecular aldol condensation, the major product formed is :
A
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 1
B
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 2
C
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 3
D
JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 4
4
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Choose the correct set of reagents for the following conversion.

JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Haloalkanes and Haloarenes Question 6 English
A
$\mathrm{Cl}_2 /$ anhy $\cdot \mathrm{AlCl}_3 ; \mathrm{Br}_2 / \mathrm{Fe} ;$ alc. KOH
B
$\mathrm{Cl}_2 / \mathrm{Fe} ; \mathrm{Br}_2 /$ anhy. $\mathrm{AlCl}_3$; aq. KOH
C
$\mathrm{Br}_2 / \mathrm{Fe} ; \mathrm{Cl}_2, \Delta$; alc. KOH
D
$\mathrm{Br}_2 /$ anhy. $\mathrm{AlCl}_3 ; \mathrm{Cl}_2, \Delta$; aq. KOH
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