1
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match the LIST-I with LIST-II

LIST-I
(Complex/ Species)
LIST-II
(Shape & magnetic moment)
A. [Ni(CO)4]I. Tetrahedral, 2.8 BM
B. [Ni(CN)4]2–II. Square planar, 0 BM
C. [NiCl4]2–III. Tetrahedral, 0 BM
D. [MnBr4]2–IV. Tetrahedral, 5.9 BM

Choose the correct answer from the options given below:

A

A-I, B-II, C-III, D-IV

B

A-IV, B-I, C-III, D-II

C

A-III, B-II, C-I, D-IV

D

A-III, B-IV, C-II, D-I

2
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match the LIST-I with LIST-II

LIST-I LIST-II
A. Carbocation I. Species that can supply a pair of electrons.
B. C-Free radical II. Species that can receive a pair of electrons.
C. Nucleophile III. sp2 hybridized carbon with empty p-orbital.
D. Electrophile IV. sp2/sp3 hybridized carbon with one unpaired electron.

Choose the correct answer from the options given below:

A

A-IV, B-II, C-III, D-I

B

A-II, B-III, C-I, D-IV

C

A-III, B-IV, C-I, D-II

D

A-III, B-IV, C-II, D-I

3
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

In a first order decomposition reaction, the time taken for the decomposition of reactant to one fourth and one eighth of its initial concentration are $t_1$ and $t_2$ (s), respectively. The ratio $t_1/t_2$ will be:

A

$\frac{4}{3}$

B

$\frac{3}{2}$

C

$\frac{3}{4}$

D

$\frac{2}{3}$

4
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Correct statements for an element with atomic number 9 are:

A. There can be 5 electrons for which $m_s = +\frac{1}{2}$ and 4 electrons for which $m_s = -\frac{1}{2}$.

B. There is only one electron in $p_z$ orbital.

C. The last electron goes to orbital with $n = 2$ and $l = 1$.

D. The sum of angular nodes of all the atomic orbitals is 1.

Choose the correct answer from the options given below:

A

A and B Only

B

A, C and D Only

C

A and C Only

D

C and D Only

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