1
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Identify the product A and product B in the following set of reactions.

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Hydrocarbons Question 9 English

A
JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Hydrocarbons Question 9 English Option 1
B
JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Hydrocarbons Question 9 English Option 2
C
JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Hydrocarbons Question 9 English Option 3
D
JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Hydrocarbons Question 9 English Option 4
2
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

The molar conductivity for electrolytes $$A$$ and $$B$$ are plotted against $$C^{3 / 2}$$ as shown below. Electrolytes $$A$$ and $$B$$ respectively are:

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Electrochemistry Question 14 English

A
A - weak electrolyte $$\quad$$ B - weak electrolyte
B
A - weak electrolyte $$\quad$$ B - strong electrolyte
C
A - strong electrolyte $$\quad$$ B - strong electrolyte
D
A - strong electrolyte $$\quad$$ B - weak electrolyte
3
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Given below are two statements :

Statement (I) : The oxidation state of an element in a particular compound is the charge acquired by its atom on the basis of electron gain enthalpy consideration from other atoms in the molecule.

Statement (II) : $$\mathrm{p} \pi-\mathrm{p} \pi$$ bond formation is more prevalent in second period elements over other periods.

In the light of the above statements, choose the most appropriate answer from the options given below :

A
Statement I is correct but Statement II is incorrect
B
Both Statement I and Statement II are correct
C
Statement I is incorrect but Statement II is correct
D
Both Statement I and Statement II are incorrect
4
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

$$0.05 \mathrm{M} \mathrm{~CuSO}_4$$ when treated with $$0.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ gives green colour solution of $$\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7$$. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane]

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Solutions Question 9 English

Due to osmosis :

A
Molarity of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ solution is lowered.
B
Green colour formation observed on side Y.
C
Molarity of $$\mathrm{CuSO}_4$$ solution is lowered.
D
Green colour formation observed on side X.
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