1
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Products A and B formed in the following set of reactions are

JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 12 English

A
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 12 English Option 1
B
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 12 English Option 2
C
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 12 English Option 3
D
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 12 English Option 4
2
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The orange colour of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ and purple colour of $$\mathrm{KMnO}_4$$ is due to

A
Charge transfer transition in both.
B
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in $$\mathrm{KMnO}_4$$ and charge transfer transitions in $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$.
C
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in both
D
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ and charge transfer transitions in $$\mathrm{KMnO}_4$$.
3
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The coordination geometry around the manganese in decacarbonyldimanganese $$(0)$$ is

A
Trigonal bipyramidal
B
Square pyramidal
C
Square planar
D
Octahedral
4
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Reduction potential of ions are given below:

$$\begin{array}{ccc} \mathrm{ClO}_4^{-} & \mathrm{IO}_4^{-} & \mathrm{BrO}_4^{-} \\ \mathrm{E}^{\circ}=1.19 \mathrm{~V} & \mathrm{E}^{\circ}=1.65 \mathrm{~V} & \mathrm{E}^{\circ}=1.74 \mathrm{~V} \end{array}$$

The correct order of their oxidising power is :

A
$$\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}$$
B
$$\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}$$
C
$$\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}$$
D
$$\mathrm{BrO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{ClO}_4^{-}$$
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