1
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The solution from the following with highest depression in freezing point/lowest freezing point is

A
$$180 \mathrm{~g}$$ of acetic acid dissolved in benzene
B
$$180 \mathrm{~g}$$ of acetic acid dissolved in water
C
$$180 \mathrm{~g}$$ of benzoic acid dissolved in benzene
D
$$180 \mathrm{~g}$$ of glucose dissolved in water
2
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements:

Statement - I: Since Fluorine is more electronegative than nitrogen, the net dipole moment of $$\mathrm{NF}_3$$ is greater than $$\mathrm{NH}_3$$.

Statement - II: In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair and the dipole moment of $$\mathrm{NH}$$ bonds are in opposite direction, but in $$\mathrm{NF}_3$$ the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction.

In the light of the above statements, choose the most appropriate from the options given below:

A
Statement I is true but Statement II is false.
B
Both Statement I and Statement II are true.
C
Both Statement I and Statement II are false.
D
Statement I is false but Statement II is true.
3
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A and B formed in the following reactions are:

$$\begin{aligned} & \mathrm{CrO}_2 \mathrm{Cl}_2+4 \mathrm{NaOH} \rightarrow \mathrm{A}+2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O}, \\ & \mathrm{A}+2 \mathrm{HCl}+2 \mathrm{H}_2 \mathrm{O}_2 \rightarrow \mathrm{B}+3 \mathrm{H}_2 \mathrm{O} \end{aligned}$$

A
$$\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7, \mathrm{~B}=\mathrm{CrO}_5$$
B
$$\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5$$
C
$$\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_4, \mathrm{~B}=\mathrm{CrO}_4$$
D
$$\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7, \mathrm{~B}=\mathrm{CrO}_3$$
4
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If a substance '$$A$$' dissolves in solution of a mixture of '$$B$$' and '$$C$$' with their respective number of moles as $$\mathrm{n}_{\mathrm{A}}, \mathrm{n}_{\mathrm{B}}$$ and $$\mathrm{n}_{\mathrm{C}_3}$$. Mole fraction of $$\mathrm{C}$$ in the solution is

A
$$\frac{n_C}{n_A \times n_B \times n_C}$$
B
$$\frac{n_B}{n_A+n_B}$$
C
$$\frac{n_C}{n_A+n_B+n_C}$$
D
$$\frac{n_C}{n_A-n_B-n_C}$$
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