1
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The total kinetic energy of 1 mole of oxygen at $$27^{\circ} \mathrm{C}$$ is : [Use universal gas constant $$(R)=8.31 \mathrm{~J} /$$ mole K]

A
6232.5 J
B
5670.5 J
C
6845.5 J
D
5942.0 J
2
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The truth table of the given circuit diagram is :

JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 19 English

A
JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 19 English Option 1
B
JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 19 English Option 2
C
JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 19 English Option 3
D
JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 19 English Option 4
3
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A current of $$200 \mu \mathrm{A}$$ deflects the coil of a moving coil galvanometer through $$60^{\circ}$$. The current to cause deflection through $$\frac{\pi}{10}$$ radian is :

A
120 $$\mu$$A
B
180 $$\mu$$A
C
30 $$\mu$$A
D
60 $$\mu$$A
4
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Wheatstone bridge principle is used to measure the specific resistance $$\left(S_1\right)$$ of given wire, having length $$L$$, radius $$r$$. If $$X$$ is the resistance of wire, then specific resistance is ; $$S_1=X\left(\frac{\pi r^2}{L}\right)$$. If the length of the wire gets doubled then the value of specific resistance will be :

A
$$\frac{S_1}{4}$$
B
$$2 \mathrm{~S}_1$$
C
$$\frac{\mathrm{S}_1}{2}$$
D
$$S_1$$
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