1
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : Work done by electric field on moving a positive charge on an equipotential surface is always zero.

Reason (R) : Electric lines of forces are always perpendicular to equipotential surfaces.

In the light of the above statements, choose the most appropriate answer from the options given below :

A
Both (A) and (R) are correct and (R) is the correct explanation of (A)
B
(A) is correct but (R) is not correct
C
Both (A) and (R) are correct but (R) is not the correct explanation of (A)
D
(A) is not correct but (R) is correct
2
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

When a polaroid sheet is rotated between two crossed polaroids then the transmitted light intensity will be maximum for a rotation of :

A
$$90^\circ$$
B
$$30^\circ$$
C
$$45^\circ$$
D
$$60^\circ$$
3
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An object is placed in a medium of refractive index 3 . An electromagnetic wave of intensity $$6 \times 10^8 \mathrm{~W} / \mathrm{m}^2$$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space $$=3 \times 10^8 \mathrm{~m} / \mathrm{s}$$ ) :

A
$$6 \mathrm{~Nm}^{-2}$$
B
$$36 \mathrm{~Nm}^{-2}$$
C
$$18 \mathrm{~Nm}^{-2}$$
D
$$2 \mathrm{~Nm}^{-2}$$
4
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The total kinetic energy of 1 mole of oxygen at $$27^{\circ} \mathrm{C}$$ is : [Use universal gas constant $$(R)=8.31 \mathrm{~J} /$$ mole K]

A
6232.5 J
B
5670.5 J
C
6845.5 J
D
5942.0 J
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