1
JEE Main 2020 (Online) 3rd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The compound A in the following reaction is : JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English
A
JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 1
B
JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 2
C
JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 3
D
JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 139 English Option 4
2
JEE Main 2020 (Online) 3rd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the following molecules and statements related to them : JEE Main 2020 (Online) 3rd September Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 138 English
(a) (B) is more likely to be crystalline than (A)
(b) (B) has higher boiling point than (A)
(c) (B) dissolves more readily than (A) in water

Identify the correct option from below :
A
only (a) is true
B
(a), (b) and (c) are true
C
(b) and (c) are true
D
(a) and (b) are true
3
JEE Main 2020 (Online) 3rd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc.H2SO4 loses 13.5% of its original mass, the correct molecular formula of A is :
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
A
[Cr(H2O)5Cl]Cl2.H2O
B
[Cr(H2O)4Cl2]Cl.2H2O
C
[Cr(H2O)3Cl3].3H2O
D
[Cr(H2O)6]Cl3
4
JEE Main 2020 (Online) 3rd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the reaction
2A + 3B + $${3 \over 2}$$C $$ \to $$ 3P, which statement is correct ?
A
$${{d{n_A}} \over {dt}} = {{d{n_B}} \over {dt}} = {{d{n_C}} \over {dt}}$$
B
$${{d{n_A}} \over {dt}} = {2 \over 3}{{d{n_B}} \over {dt}} = {3 \over 4}{{d{n_C}} \over {dt}}$$
C
$${{d{n_A}} \over {dt}} = {3 \over 2}{{d{n_B}} \over {dt}} = {3 \over 4}{{d{n_C}} \over {dt}}$$
D
$${{d{n_A}} \over {dt}} = {2 \over 3}{{d{n_B}} \over {dt}} = {4 \over 3}{{d{n_C}} \over {dt}}$$
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