1
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
The function $$f:R/\left\{ 0 \right\} \to R$$ given by

$$f\left( x \right) = {1 \over x} - {2 \over {{e^{2x}} - 1}}$$

can be made continuous at $$x$$ = 0 by defining $$f$$(0) as
A
0
B
1
C
2
D
$$-1$$
2
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
Let $$f:R \to R$$ be a function defined by

$$f(x) = \min \left\{ {x + 1,\left| x \right| + 1} \right\}$$, then which of the following is true?
A
$$f(x)$$ is differentiale everywhere
B
$$f(x)$$ is not differentiable at x = 0
C
$$f(x) > 1$$ for all $$x \in R$$
D
$$f(x)$$ is not differentiable at x = 1
3
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
The largest interval lying in $$\left( { - {\pi \over 2},{\pi \over 2}} \right)$$ for which the function

$$f\left( x \right) = {4^{ - {x^2}}} + {\cos ^{ - 1}}\left( {{x \over 2} - 1} \right)$$$$ + \log \left( {\cos x} \right)$$,

is defined, is
A
$$\left[ { - {\pi \over 4},{\pi \over 2}} \right)$$
B
$$\left[ {0,{\pi \over 2}} \right)$$
C
$$\left[ {0,\pi } \right]$$
D
$$\left( { - {\pi \over 2},{\pi \over 2}} \right)$$
4
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
If sin-1$$\left( {{x \over 5}} \right)$$ + cosec-1$$\left( {{5 \over 4}} \right)$$ = $${\pi \over 2}$$, then the value of x is :
A
4
B
5
C
1
D
3
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