1
JEE Main 2014 (Offline)
+4
-1
Resistance of 0.2 M solution of an electrolyte is 50 $$\Omega$$. The specific conductance of the solution is 1.4 S m-1. The resistance of 0.5 M solution of the same electrolyte is 280 $$\Omega$$. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol-1 is :
A
5 × 103
B
5 × 102
C
5 × 10-4
D
5 × 10-3
2
JEE Main 2014 (Offline)
+4
-1
Given below are the half-cell reactions:

Mn2+ + 2e- $$\to$$ Mn; Eo = -1.18 V

2(Mn3+ + e- $$\to$$ Mn2+); Eo = +1.51 V

The Eo for 3Mn2+ $$\to$$ Mn + 2Mn3+ will be :
A
– 0.33 V; the reaction will not occur
B
– 0.33 V; the reaction will occur
C
– 2.69 V; the reaction will not occur
D
– 2.69 V; the reaction will occur
3
JEE Main 2014 (Offline)
+4
-1
The equivalent conductance of NaCl at concentration C and at infinite dilution are $${\lambda _C}$$ and $${\lambda _\infty }$$, respectively. The correct relationship between $${\lambda _C}$$ and $${\lambda _\infty }$$ is given as: (where the constant B is positive)
A
$${\lambda _C} = {\lambda _\infty } + (B)C$$
B
$${\lambda _C} = {\lambda _\infty } - (B)C$$
C
$${\lambda _C} = {\lambda _\infty } - (B)\sqrt C$$
D
$${\lambda _C} = {\lambda _\infty } + (B)\sqrt C$$
4
JEE Main 2013 (Offline)
+4
-1
Given

$$E_{C{r^{2 + }}/Cr}^o$$ = -0.74 V; $$E_{MnO_4^ - /M{n^{2 + }}}^o$$ = 1.51 V

$$E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o$$ = 1.33 V; $$E_{Cl/C{l^ - }}^o$$ = 1.36 V

Based on the data given above, strongest oxidising agent will be :
A
Cr3+
B
Mn2+
C
$$MnO_4^ -$$
D
Cl-
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