1
JEE Main 2020 (Online) 2nd September Morning Slot
+4
-1
If R = {(x, y) : x, y $$\in$$ Z, x2 + 3y2 $$\le$$ 8} is a relation on the set of integers Z, then the domain of R–1 is :
A
{0, 1}
B
{–2, –1, 1, 2}
C
{–1, 0, 1}
D
{–2, –1, 0, 1, 2}
2
JEE Main 2020 (Online) 2nd September Morning Slot
+4
-1
The domain of the function
f(x) = $${\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)$$ is (– $$\infty$$, -a]$$\cup$$[a, $$\infty$$). Then a is equal to :
A
$${{\sqrt {17} - 1} \over 2}$$
B
$${{1 + \sqrt {17} } \over 2}$$
C
$${{\sqrt {17} } \over 2} + 1$$
D
$${{\sqrt {17} } \over 2}$$
3
JEE Main 2020 (Online) 9th January Evening Slot
+4
-1
If A = {x $$\in$$ R : |x| < 2} and B = {x $$\in$$ R : |x – 2| $$\ge$$ 3}; then :
A
A – B = [–1, 2)
B
A $$\cup$$ B = R – (2, 5)
C
A $$\cap$$ B = (–2, –1)
D
B – A = R – (–2, 5)
4
JEE Main 2020 (Online) 9th January Evening Slot
+4
-1
Let a – 2b + c = 1.

If $$f(x)=\left| {\matrix{ {x + a} & {x + 2} & {x + 1} \cr {x + b} & {x + 3} & {x + 2} \cr {x + c} & {x + 4} & {x + 3} \cr } } \right|$$, then:
A
ƒ(50) = 1
B
ƒ(–50) = –1
C
ƒ(50) = –501
D
ƒ(–50) = 501
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