1
JEE Main 2019 (Online) 9th January Evening Slot
+4
-1
Charge is distributed within a sphere of radius R with a volume charge density $$\rho \left( r \right) = {A \over {{r^2}}}{e^{ - {{2r} \over s}}},$$ where A and a are constants. If Q is the total charge of this charge distribution, the radius R is :
A
a log $$\left( {1 - {Q \over {2\pi aA}}} \right)$$
B
$${a \over 2}$$ log $$\left( {{1 \over {1 - {Q \over {2\pi aA}}}}} \right)$$
C
a log $$\left( {{1 \over {1 - {Q \over {2\pi aA}}}}} \right)$$
D
$${a \over 2}$$ log $$\left( {1 - {Q \over {2\pi aA}}} \right)$$
2
JEE Main 2019 (Online) 9th January Morning Slot
+4
-1
Three charges + Q, q, + Q are placed respectively, at distance, 0, d/2 and d from the origin, on the x-axis. If the net force experienced by + Q, placed at x = 0, is zero, then value of q is :
A
$$-$$ $${Q \over 4}$$
B
+ $${Q \over 2}$$
C
+ $${Q \over 4}$$
D
$$-$$ $${Q \over 2}$$
3
JEE Main 2019 (Online) 9th January Morning Slot
+4
-1
For a uniformly charged ring of radius R, the electric field on its axis has the largest magnitude at a distance h from its center. Then value of h is :
A
$${R \over {\sqrt 5 }}$$
B
$${R \over {\sqrt 2 }}$$
C
R
D
R$$\sqrt 2$$
4
JEE Main 2018 (Online) 16th April Morning Slot
+4
-1
Two identical conducting spheres A and B, carry equal charge. They are separated by a distance much larger than their diameters, and the force between theis F. A third identical conducting sphere, C, is uncharged. Sphere C is first touhed to A, then to B, and then removed. As a result, the force between A and B would be equal to :
A
F
B
$${{3F} \over 4}$$
C
$${{3F} \over 8}$$
D
$${{F} \over 2}$$
EXAM MAP
Medical
NEET