JEE Main 2019 (Online) 9th January Morning Slot | Heat and Thermodynamics Question 316 | Physics

A rod, of length L at room temperature and uniform area of cross section A, is made of a metal having coefficient of linear expansion $$\alpha $$/^oC. It is observed that an external compressive force F, is applied on each of its ends, prevents any change in the length of the rod, when its temperature rises by $$\Delta $$TK. Young's modulus, Y, for this metal is :

$${F \over {A\alpha \Delta T}}$$

$${F \over {A\alpha (\Delta T - 273)}}$$

$${F \over {2A\alpha \Delta T}}$$

$${{2F} \over {A\alpha \Delta T}}$$

JEE Main 2018 (Online) 16th April Morning Slot

MCQ (Single Correct Answer)

-1

One mole of an ideal monoatomic gas is taken along the path ABCA as show in the PV diagram. The maximum temperature attained by the gas along the path BC is given by :

JEE Main 2018 (Online) 16th April Morning Slot Physics - Heat and Thermodynamics Question 329 English

JEE Main 2018 (Online) 16th April Morning Slot Physics - Heat and Thermodynamics Question 329 English

$${{25} \over {16}}\,{{{P_o}{V_o}} \over R}$$

$${{25} \over {8}}\,{{{P_o}{V_o}} \over R}$$

$${{25} \over {4}}\,{{{P_o}{V_o}} \over R}$$

$${{5} \over {8}}\,{{{P_o}{V_o}} \over R}$$

JEE Main 2018 (Online) 16th April Morning Slot

MCQ (Single Correct Answer)

-1

Two moles of helium are mixed with n moles of hydrogen. If $${{Cp} \over {Cv}} = {3 \over 2}$$ for the mixture, then the value of n is :

3 / 2

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

-1

Two moles of an ideal monatomic gas occupies a volume V at 27^oC. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.

(a) 195 K (b) 2.7 kJ

(a) 189 K (b) 2.7 kJ

(a) 195 K (b) –2.7 kJ

(a) 189 K (b) – 2.7 kJ

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