1
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

An alternating current is represented by the equation, $i=100 \sqrt{2} \sin (100 \pi t)$ ampere. The RMS value of current and the frequency of the given alternating current are

A
$\frac{100}{\sqrt{2}} \mathrm{~A}, 100 \mathrm{~Hz}$
B
$50 \sqrt{2} \mathrm{~A}, 50 \mathrm{~Hz}$
C
$100 \sqrt{2} \mathrm{~A}, 100 \mathrm{~Hz}$
D
$100 \mathrm{~A}, 50 \mathrm{~Hz}$
2
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two liquids $A$ and $B$ have $\theta_A$ and $\theta_B$ as contact angles in a capillary tube. If $K=\cos \theta_A / \cos \theta_B$, then identify the correct statement:

A
K is negative, then liquid A and liquid B have convex meniscus.
B
$K$ is negative, then liquid $A$ and liquid $B$ have concave meniscus.
C
K is zero, then liquid A has convex meniscus and liquid B has concave meniscus.
D
K is negative, then liquid A has concave meniscus and liquid B has convex meniscus.
3
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Which of the following are correct expression for torque acting on a body?

A. $\vec{\tau}=\vec{r} \times \vec{L}$

B. $\vec{\tau}=\frac{d}{d t}(\vec{r} \times \vec{p})$

C. $\vec{\tau}=\vec{r} \times \frac{d \vec{p}}{d t}$

D. $\vec{\tau}=I \vec{\alpha}$

E. $\vec{\tau}=\vec{r} \times \vec{F}$

( $\vec{r}=$ position vector; $\vec{p}=$ linear momentum; $\vec{L}=$ angular momentum; $\vec{\alpha}=$ angular acceleration; $I=$ moment of inertia; $\vec{F}=$ force; $t=$ time)

Choose the correct answer from the options given below:

A
A, B, D and E Only
B
C and D Only
C
B, C, D and E Only
D
B, D and E Only
4
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two infinite identical charged sheets and a charged spherical body of charge density ' $\rho$ ' are arranged as shown in figure. Then the correct relation between the electrical fields at $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D points is:

JEE Main 2025 (Online) 4th April Morning Shift Physics - Electrostatics Question 2 English

A
$\left|\vec{E}_A\right|=\left|\vec{E}_B\right| ; \vec{E}_C>\vec{E}_D$
B
$\vec{E}_A=\vec{E}_B ; \vec{E}_C=\vec{E}_D$
C
$\vec{E}_C \neq \vec{E}_D ; \vec{E}_A>\vec{E}_B$
D
$\vec{E}_A>\vec{E}_B ; \vec{E}_C=\vec{E}_D$
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