1
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg . The mole fraction of the solute in the solution is 0.2 . What would be the mole fraction of the solvent if decrease in vapour pressure is 20 mm of Hg ?

A
0.2
B
0.4
C
0.8
D
0.6
2
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List - I with List - II

List - I List - II
(A) Bronze (I) Cu, Ni
(B) Brass (II) Fe, Cr, Ni, C
(C) UK silver coin (III) Cu, Zn
(D) Stainless steel (IV) Cu, Sn

Choose the correct answer from the options given below :

A
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
B
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
C
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
D
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
3
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider a binary solution of two volatile liquid components 1 and $2 . x_1$ and $y_1$ are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of $\frac{1}{x_1}$ vs $\frac{1}{y_1}$ are given respectively as :

A
$\frac{\mathrm{P}_1^0}{\mathrm{P}_2^0}, \frac{\mathrm{P}_1^0-\mathrm{P}_2^0}{\mathrm{P}_2^0}$
B
$\frac{\mathrm{P}_2^0}{\mathrm{P}_1^0}, \frac{\mathrm{P}_2^0-\mathrm{P}_1^0}{\mathrm{P}_2^0}$
C
$\frac{\mathrm{P}_2^0}{\mathrm{P}_1^0}, \frac{\mathrm{P}_1^0-\mathrm{P}_2^0}{\mathrm{P}_2^0}$
D
$\frac{\mathrm{P}_1^0}{\mathrm{P}_2^0}, \frac{\mathrm{P}_2^0-\mathrm{P}_1^0}{\mathrm{P}_2^0}$
4
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are the atomic numbers of some group 14 elements. The atomic number of the element with lowest melting point is :

A
14
B
50
C
6
D
82
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