1
JEE Main 2024 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electrostatic force $$\left(\vec{F_1}\right)$$ and magnetic force $$\left(\vec{F}_2\right)$$ acting on a charge $$q$$ moving with velocity $$v$$ can be written :

A
$$\vec{F}_1=q \vec{B}, \vec{F}_2=q(\vec{B} \times \vec{v})$$
B
$$\vec{F}_1=q \vec{V} \cdot \vec{E}, \vec{F}_2=q(\vec{B} \cdot \vec{V})$$
C
$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{V} \times \vec{B})$$
D
$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{B} \times \vec{V})$$
2
JEE Main 2024 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If $$\mathrm{n}$$ is the number density and $$\mathrm{d}$$ is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :

A
$$\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}$$
B
$$\frac{1}{\sqrt{2} n^2 \pi^2 d^2}$$
C
$$\frac{1}{\sqrt{2 n \pi d^2}}$$
D
$$\sqrt{2} \mathrm{n} \pi \mathrm{d}^2$$
3
JEE Main 2024 (Online) 5th April Evening Shift
Numerical
+4
-1
Change Language

The electric field at point $$\mathrm{p}$$ due to an electric dipole is $$\mathrm{E}$$. The electric field at point $$\mathrm{R}$$ on equitorial line will be $$\frac{\mathrm{E}}{x}$$. The value of $$x$$ :

JEE Main 2024 (Online) 5th April Evening Shift Physics - Electrostatics Question 4 English

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4
JEE Main 2024 (Online) 5th April Evening Shift
Numerical
+4
-1
Change Language

A sonometer wire of resonating length $$90 \mathrm{~cm}$$ has a fundamental frequency of $$400 \mathrm{~Hz}$$ when kept under some tension. The resonating length of the wire with fundamental frequency of $$600 \mathrm{~Hz}$$ under same tension _______ $$\mathrm{cm}$$.

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