The equation of common tangent to the curves y² = 16x and xy = –4, is :

A plane which bisects the angle between the two given planes 2x – y + 2z – 4 = 0 and x + 2y + 2z – 2 = 0, passes through the point :

The Boolean expression ~(p $$ \Rightarrow $$ (~q)) is equivalent to :

A triangle has a vertex at (1, 2) and the mid points of the two sides through it are (–1, 1) and (2, 3). Then the centroid of this triangle is :